Prompting the user to enter ' f ' to end the program.?

How to end a program with a character in C programming.





I have this sample program below, which I would like to add a character like ' F' that ends the program when the user inputs that character.








#include %26lt;stdio.h%26gt;


#include %26lt;math.h%26gt;





int main(){





int binary=0;


int decimal=0;


int digits=0;





while(1){


printf("Input in Binary: ");


fflush(stdin);


scanf("%i",%26amp;binary);





for(int i=1;binary%26gt;=i;i*=10){


digits++;


}





for(int i=(digits-1);i%26gt;=0;i--){


if((binary-pow(10.0,i))%26gt;=0){


decimal+=1%26lt;%26lt;i;


binary-=pow(10.0,i);


}


}


digits=0;


printf("\nOutput in decimal: %i\n\n",decimal);


}





return 0;


}











the problem is that the variable "binary" is of integer, I need to switch it to character, but it should still work.





I tried doing this:





if(binary=='f')


break;





but since binary is integer, when I enter f, the program keeps looping and it does not stop.





How can I solve this issue?|||After you do the final output, ask the user if they want to continue or not in such a way that a 'F' indicates no. Then, instead of doing a while (1) (which is bad coding -- it not only forces the loop to end from scattered places within itself, it also shows the coder didn't really know how the loop was going to work), do this:



char Response = ''; // Note: Those are two single quotes, not one double quote.



while ( Response != 'F' %26amp;%26amp; Response != 'f' )

{





// Ask here and read the answer into Response



}



Hope that helps.|||Use char instead of int, but make a seperate variable for doing this.





Char exitProgram;





At the end of the program, just grab the users input when asked to quit, and run it through an if/then/else loop.|||I added a new variable "char binarychar" and changed the way you get the user input by a bit. This time, the scanf "tries" to get the user input and checks to see whether the input is even correct or not. If the input was truly a number, then the scanf returns true, and thus the if statement i used does not activate. Otherwise, if the userinput was "not" a number, then the scanf would return false, thus triggering the if statement. And inside the if statement, it assumes that if the userinput was not a number, then it must be a character. And so, it attemps to scanf a character. If the character is an 'f' or 'F', then it breaks the loop and thus reaches the end of the program.



#include %26lt;stdio.h%26gt;

#include %26lt;math.h%26gt;



int main(){



int binary=0;

int decimal=0;

int digits=0;

char binarychar;



while(1){

printf("Input in Binary: ");

fflush(stdin);

if(scanf("%i",%26amp;binary)==false){

scanf("%c",%26amp;binarychar);

if((binarychar=='f')

||(binarychar=='F')){

break;

}

}





for(int i=1;binary%26gt;=i;i*=10){

digits++;

}



for(int i=(digits-1);i%26gt;=0;i--){

if((binary-pow(10.0,i))%26gt;=0){

decimal+=1%26lt;%26lt;i;

binary-=pow(10.0,i);

}

}

digits=0;

printf("\nOutput in decimal: %i\n\n",decimal);

}



return 0;

}