Using Truth Table, prove that C=(A'+B)'=A.B' where A, B and C are binary logical variables. Show a diagram?

showing the output C from inputs A and B using '2-input NOR' gates only. Especially do the 2nd part.|||OR Gate Binary

_______

A | B | C

------------

0 | 0 | 1

0 | 1 | 0

1 | 0 | 0

1 | 1 | 0



Circuit Binary Out

_______

A | B | A*B'

------------

0 | 0 | 0

0 | 1 | 0

1 | 0 | 1

1 | 1 | 0



Is this what you wanted?





A NOR gate is the inverse of an OR. Is the "B" input of gates NOR as well? Is this an exclusive NOR? Please specify...